FeaturesHow It WorksFor ParentsPricingContactLog inStart free — no credit card needed →

Chemistry · Unit 2 · Aqueous solutions and acidity · Aqueous solutions and molarity

Apply the mole concept to calculate moles of solute, concentratio n and volume of a solution. (Formula: Molarity/Concentration (c) = moles of solute ( n) volume of solution (V)) Identifying ions in solution

Practise this objective

AI-marked practice questions tied to QCAA mark schemes for this exact LO. Free to start.

Start free practice

Practice questions for this objective

Full questions, answers and worked solutions unlock when you start a free practice session.

Question 1

A 25.0 mL aliquot of aqueous sulfuric acid (H₂SO₄) with a concentration of 0.200 mol L⁻¹ was diluted with 475.0 mL of water to make a final volume of 500.0 mL. Calculate the concentration of H⁺ ions in the final solution.

Worked answer
🔒 Start free to see full answer
Question 2

A 25.0 mL aliquot of 0.150 M sulfuric acid (H₂SO₄) solution was diluted with water to a final volume of 250.0 mL. What is the concentration of sulfate ions (SO₄²⁻) in the diluted solution?

Worked answer
🔒 Start free to see full answer
Question 3

A student prepares a solution by dissolving 8.5 g of sodium chloride (NaCl) in water and diluting to a final volume of 500 mL. (Relative atomic masses: Na = 23, Cl = 35.5) (a) Calculate the number of moles of NaCl dissolved. [1] (b) Calculate the concentration of the sodium chloride solution in mol/L. [1]

Worked answer
🔒 Start free to see full answer
Unlock all 3 answers — free

More in Aqueous solutions and molarity

← Previous
Apply the Arrhenius model to explain the behaviour of strong and weak acids and bases in aqueous solutions. Reactions of acids
Next →
Apply the pH scale to compare the levels of acidity or alkalinity of aqueous solutions.
All LOs in Aqueous solutions and molarityBack to full Chemistry syllabus