For the reaction: $\mathrm{N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g)}$, the equilibrium constant is $K_c = 0.50 \text{ mol}^{-2}\text{dm}^6$ at 450 K. At a given moment, the reaction quotient is calculated as $Q = 0.15 \text{ mol}^{-2}\text{dm}^6$. In which direction will the reaction shift to reach equilibrium?
Chemistry · Unit 3 · Chemical equilibrium systems · Chemical equilibrium
Infer shifts in equilibrium reactions using equilibrium constants (Kc) and reaction quotients (Q).
Practise this objective
AI-marked practice questions tied to QCAA mark schemes for this exact LO. Free to start.
Start free practicePractice questions for this objective
Full questions, answers and worked solutions unlock when you start a free practice session.
For the reaction $$\ce{N2O4(g) <=> 2NO2(g)}$$ at 298 K, $$K_c = 0.142$$. At a particular moment, the concentrations are $$[\ce{N2O4}] = 0.080 \text{ mol L}^{-1}$$ and $$[\ce{NO2}] = 0.025 \text{ mol L}^{-1}$$. Determine whether the reaction will shift to the left or to the right to reach equilibrium, and explain your reasoning.
The system $$\text{N}_2(g) + 3\text{H}_2(g) \rightleftharpoons 2\text{NH}_3(g)$$ has $$K_c = 0.50$$ at a particular temperature. At a given moment, the reaction quotient $$Q = 0.20$$. Which statement correctly describes how the equilibrium will shift?