Calculate cell potential, 𝐸cell o (Formula: 𝐸cell o = 𝐸reduction half−cell o − 𝐸oxidation half−cell o)

A galvanic cell is constructed using a copper electrode in copper(II) sulfate solution and a nickel electrode in nickel(II) chloride solution, connected by a salt bridge. Standard reduction potentials: - Cu²⁺(aq) + 2e⁻ → Cu(s): E° = +0.34 V - Ni²⁺(aq) + 2e⁻ → Ni(s): E° = −0.26 V (a) Write the cell notation for this galvanic cell. [1 mark] (b) Calculate the standard cell potential (E°cell) for this cell. Show your working. [2 marks]

A galvanic cell is constructed using a nickel electrode in $\text{Ni}^{2+}(\text{aq})$ and a copper electrode in $\text{Cu}^{2+}(\text{aq})$. Calculate the standard cell potential, $E_\text{cell}^\circ$, for this cell. (Use the standard reduction potentials: $E^\circ(\text{Ni}^{2+}/\text{Ni}) = -0.26 \text{ V}$ and $E^\circ(\text{Cu}^{2+}/\text{Cu}) = +0.34 \text{ V}$)

Calculate the standard cell potential for the galvanic cell shown in the diagram.

Calculate the cell potential for the galvanic cell under standard conditions. Standard reduction potentials: $$\ce{Ni^{2+}(aq) + 2e^- -> Ni(s)}\quad E^{\circ} = -0.26\,\text{V}$$ $$\ce{Ag^{+}(aq) + e^- -> Ag(s)}\quad E^{\circ} = +0.80\,\text{V}$$