FeaturesHow It WorksFor ParentsPricingContactLog inStart free — no credit card needed →

Specialist Mathematics · Unit 2 · Circle and geometric proofs · Geometric proofs using vectors

Prove the diagonals of a parallelogram meet at right angles if and only if it is a rhombus.

Practise this objective

AI-marked practice questions tied to QCAA mark schemes for this exact LO. Free to start.

Start free practice

Practice questions for this objective

Full questions, answers and worked solutions unlock when you start a free practice session.

Question 1

Let \(ABCD\) be a parallelogram with adjacent sides represented by vectors \(\vec{a}\) and \(\vec{b}\). Prove that the diagonals of the parallelogram are perpendicular if and only if \(|\vec{a}| = |\vec{b}|\).

Worked answer
🔒 Start free to see full answer
Question 2

The diagram shows parallelogram OABC with position vectors $\vec{OA} = \mathbf{a}$ and $\vec{OC} = \mathbf{c}$. Prove that the diagonals of the parallelogram meet at right angles if and only if it is a rhombus.

Worked answer
🔒 Start free to see full answer
Question 3

A quadrilateral \(PQRS\) has vertices with position vectors \(\vec{p}\), \(\vec{q}\), \(\vec{r}\), and \(\vec{s}\). The quadrilateral is a parallelogram with \(\vec{PQ} = \vec{SR}\). Prove that if the diagonals \(PR\) and \(QS\) meet at right angles, then \(|\vec{PQ}| = |\vec{PS}|\).

Worked answer
🔒 Start free to see full answer
Unlock all 3 answers — free

More in Geometric proofs using vectors

← Previous
Prove midpoints of the sides of a quadrilateral join to form a parallelogram.
Next →
Prove the sum of the squares of the lengths of a parallelogram’s diagonals is equal to the sum of the squares of the lengths of the sides.
All LOs in Geometric proofs using vectorsBack to full Specialist Mathematics syllabus