FeaturesHow It WorksFor ParentsPricingContactLog inStart free — no credit card needed →

Specialist Mathematics · Unit 4 · Applications of integral calculus · Applications of integral calculus

Apply techniques from Unit 4 Topic 1 Sub-topic: Integration techniques to calculate areas between curves determined by functions, with and without technology.

Practise this objective

AI-marked practice questions tied to QCAA mark schemes for this exact LO. Free to start.

Start free practice

Practice questions for this objective

Full questions, answers and worked solutions unlock when you start a free practice session.

Question 1

A region is bounded by the curves where \(f(x) = e^{0.5x}\) and \(g(x) = 2\ln(x + 1) + 1\), and the vertical lines \(x = 0\) and \(x = 3\). The table below shows values of both functions at regular intervals over this domain. (a) Using algebraic techniques and the table of values, identify which function forms the upper boundary over the interval. (1 mark) (b) Set up the integral required to calculate the area of the shaded region. (1 mark) (c) Use technology (graphing calculator or computer algebra system) to evaluate the integral and determine the area of the region bounded by the two curves, correct to 2 decimal places. (2 marks)

Worked answer
🔒 Start free to see full answer
Question 2

The region R is bounded by the curves y = sin(2x) and y = cos(x) − 1 for 0 ≤ x ≤ π. (a) Determine the x-coordinates of the points where the curves intersect in the interval [0, π], correct to 2 decimal places. (1 mark) (b) Calculate the area of region R, correct to 2 decimal places. (3 marks)

Worked answer
🔒 Start free to see full answer
Question 3

Calculate the exact area enclosed between the curves $y = \sqrt{x}$ and $y = x^2$ from their point of intersection at the origin to their other point of intersection.

Worked answer
🔒 Start free to see full answer
Unlock all 3 answers — free

More in Applications of integral calculus

Next →
Determine volumes of solids of revolution about either axis, with and without technology. about the 𝑥-axis: 𝑉 = 𝜋 ∫ [𝑓(𝑥)]2𝑏 𝑎 𝑑𝑥 about the 𝑦-axis: 𝑉 = 𝜋 ∫ [𝑓(𝑦)]2𝑏 𝑎 𝑑𝑦
All LOs in Applications of integral calculusBack to full Specialist Mathematics syllabus