FeaturesHow It WorksFor ParentsPricingContactLog inStart free โ€” no credit card needed โ†’

Physics ยท Unit 3 ยท Gravity and motion ยท Projectile motion

Solve problems involving objects undergoing uniform circular motion at a constant speed using ๐‘ฃ = 2๐œ‹๐‘Ÿ ๐‘‡ and ๐‘Ž๐‘ = ๐‘ฃ2 ๐‘Ÿ.

Practise this objective

AI-marked practice questions tied to QCAA mark schemes for this exact LO. Free to start.

Start free practice

Practice questions for this objective

Full questions, answers and worked solutions unlock when you start a free practice session.

Question 1

A drone carries a sensor on a 2.5 m cable and flies in a horizontal circular path. The sensor completes 45 revolutions in 60 seconds. (a) Calculate the period of the sensor's motion. (b) Calculate the speed of the sensor. (c) Hence, calculate the centripetal acceleration of the sensor.

Worked answer
๐Ÿ”’ Start free to see full answer
Question 2

A drone follows a circular path of radius \(42\) m at a constant speed of \(15\) m s\(^{-1}\). Calculate the magnitude of the centripetal acceleration experienced by the drone.

Worked answer
๐Ÿ”’ Start free to see full answer
Question 3

A ball is attached to a string and rotates in a horizontal circle of radius 0.45 m. The ball completes one full revolution in 0.80 s. Calculate the centripetal acceleration of the ball. Show your working.

Worked answer
๐Ÿ”’ Start free to see full answer
Question 4

A racing car travels around a circular track of radius 85 m. The car completes one lap in 12.5 s. Calculate the magnitude of the centripetal acceleration of the car. Show your working.

Worked answer
๐Ÿ”’ Start free to see full answer
Unlock all 4 answers โ€” free

More in Projectile motion

โ† Previous
Solve problems involving forces acting on objects in uniform circular motion using ๐น๐‘ = ๐น๐‘›๐‘’๐‘ก = ๐‘š๐‘ฃ2 ๐‘Ÿ. Orbital mechanics
Next โ†’
Solve problems involving projectile motion in the absence of drag effects using ๐‘ฃ๐‘ฆ = ๐‘ข๐‘ฆ + ๐‘”๐‘ก, ๐‘ ๐‘ฆ = ๐‘ข๐‘ฆ ๐‘ก + 1 2 ๐‘”๐‘ก2, ๐‘ฃ๐‘ฆ 2 = ๐‘ข๐‘ฆ 2 + 2๐‘”๐‘ ๐‘ฆ, ๐‘ฃ๐‘ฅ = ๐‘ข๐‘ฅ and ๐‘ ๐‘ฅ = ๐‘ข๐‘ฅ๐‘ก.
All LOs in Projectile motionBack to full Physics syllabus