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Physics Β· Unit 3 Β· Gravity and motion Β· Projectile motion

Solve problems involving projectile motion in the absence of drag effects using 𝑣𝑦 = 𝑒𝑦 + 𝑔𝑑, 𝑠𝑦 = 𝑒𝑦 𝑑 + 1 2 𝑔𝑑2, 𝑣𝑦 2 = 𝑒𝑦 2 + 2𝑔𝑠𝑦, 𝑣π‘₯ = 𝑒π‘₯ and 𝑠π‘₯ = 𝑒π‘₯𝑑.

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Question 1

A tennis ball is struck horizontally from a height of 1.8 m with an initial horizontal velocity of 12 m s⁻¹. Assuming no air resistance, what is the horizontal distance travelled when the ball reaches the ground?

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Question 2

A ball is kicked from ground level with an initial velocity of 22 m s⁻¹ at an angle of 35° above the horizontal. The ball travels through the air and strikes a vertical wall. At the instant of impact, the ball is 1.8 m above the ground and has been in flight for 1.5 s. (a) Calculate the horizontal distance from the launch point to the wall. (1 mark) (b) Calculate the vertical component of the ball's velocity at the instant it strikes the wall. (2 marks) (c) Hence, determine the speed of the ball at the instant of impact with the wall. (1 mark) Take g = 9.8 m s⁻².

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Question 3

A tennis ball is served horizontally from a height of 2.4 m above the ground with an initial velocity of 18 m s$^{-1}$. Air resistance is negligible. (a) Calculate the time taken for the ball to reach the ground. (1 mark) (b) Calculate the horizontal distance travelled by the ball before it strikes the ground. (1 mark) (c) Calculate the vertical velocity of the ball at the instant it strikes the ground. (1 mark)

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Question 4

A stone is thrown horizontally from the top of a cliff with an initial speed of $18 \text{ m s}^{-1}$. Calculate the horizontal distance travelled by the stone in the first $4.2 \text{ s}$ of flight (ignoring air resistance).

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More in Projectile motion

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Solve problems involving objects undergoing uniform circular motion at a constant speed using 𝑣 = 2πœ‹π‘Ÿ 𝑇 and π‘Žπ‘ = 𝑣2 π‘Ÿ.
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Solve problems involving the gravitational field strength at a distance from an object using 𝑔 = 𝐹 π‘š = 𝐺𝑀 π‘Ÿ2.
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